计算:
(1) π 0 + ( 1 2 ) - 1 - ( 3 ) 2 ;
(2) ( x - 1 ) ( x + 1 ) - x ( x - 1 ) .
计算:(﹣4)2+(π﹣3)0﹣23﹣|﹣5|.
计算: (1)1+(﹣5) (2) (3) (4).
先化简,再求值: (1)(5a+2a2﹣3﹣4a3)﹣(﹣a+3a3﹣a2),其中a=﹣2; (2)3x2﹣[x2﹣2(3x﹣x2)],其中x=﹣7; (3)2(x2y+xy)﹣3(x2y﹣xy)﹣4x2y,其中x=1,y=﹣1.
已知:如图,△AOC≌△BOD.求证:△AOD≌△BOC.
计算:+﹣.