如图,在梯形△ABCD中,AB//CD,AD=DC-=CB=1,ABC=60。,四边形ACFE为矩形,平面ACFE上平面ABCD,CF=1.
(1)求证:BC⊥平面ACFE;
(2)若M为线段EF的中点,设平面MAB与平面FCB所成角为,求.
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如图,在梯形△ABCD中,AB//CD,AD=DC-=CB=1,ABC=60。,四边形ACFE为矩形,平面ACFE上平面ABCD,CF=1.
(1)求证:BC⊥平面ACFE;
(2)若M为线段EF的中点,设平面MAB与平面FCB所成角为,求.