在ABC中,角A,B,C的对边分别为a,b,c,若△ABC为锐角三角形,且满足 sinB ( 1 + 2 cosC ) = 2 sinAcosC + cosAsinC ,则下列等式成立的是( )
a = 2 b
b = 2 a
A = 2 B
B = 2 A