计算的值是 .
复数z=(a2-2a)+(a2-a-2)i(a∈R)对应的点在虚轴上,则a的值为________.
复数=________.
设复数z满足i(z+1)=-3+2i,则z的实部为________.
复数z与(z+2)2-8i均为纯虚数,则z=________.
如果复数z= (b∈R)的实部和虚部互为相反数,则b=________.