(本小题10分)已知AB,BC,CD分别与⊙相切于E,F,G三点,且AB∥CD,连接OB,OC.(1)如图①,求∠BOC的度数;(2)如图②,延长CO交⊙O于点M,过点M做MN∥OB交CD于点N,当OB=6,OC=8时,求⊙的半径及MN的长.
已知x+y=3,xy=5,求x2﹣xy+y2的值.
(2m﹣5)(5+2m)﹣(2m﹣5)2.
计算:(x﹣2y)(x+2y)+4y2.
先化简,再求值:5(3x2y﹣xy2)﹣4(﹣xy2+3x2y),其中x=﹣2,y=3.
计算:(1)﹣(2a﹣b)+[a﹣(3a+4b)] (2)(a+b)(a2﹣ab+b2)