如图,在正方形ABCD的边长是2,点E是BC边的中点,过点B作BG⊥AE,垂足为G,延长BG交AC于点F,连结EF. 则下列结论中:①S△CEF:S△AFB=1:4;②AB=AF; ③ ;④S四边形ABEF=.正确的序号是( )