如图,平行于x轴的直线AC分别交抛物线y1=x2(x≥0)与(x≥0)于B、C两点,过点C作y轴的平行线交y1于点D,直线DE∥AC,交y2于点E,则= .
4a2b2+(ab)2=________.
93=3m,则m=______.
计算:0.1252013×(-8)2014=______.
若ax=3,ay=2,则a2x+y=______.
计算:-(-3a2b3)4的结果是_______.