如图,将△ABC绕点A逆时针旋转80°得到△AB′C′.若∠BAC=50°,则∠CAB′的度数为 .
x2+x+____=(______)2
992-1012=________
1-a4=___________
-a2+b2=(a+b)(______)
x(a-1)(a-2)-y(1-a)(2-a)=____________.