求下列各式中x的值.(1)8x3+125=0;(2)(x+2)3=-27.
解不等式组: {3x+1<2x+3①2x>3x−12②
计算: 2−1+|−5|−sin30°+(π−1)0.
先化简,再求值: (y2x+y−y)÷x−yx2−y2−(x−2y)(x+y),其中 x=−1, y=2.
计算: −12018+(12)−2−|√3−2|−2sin60°.
(1)计算: |2−√3|+(√2+1)0−3tan30°+(−1)2018−(12)−1;
(2)解不等式组: {x+3>02(x−1)+3⩾并判断 − 1 , 2 这两个数是否为该不等式组的解.