设等差数列 $\left\{a_n\right\}$的前 $n$项和为 $S_n$，且 $S_4=4S_2$, $a_{2n}=2a_n+1$.
(Ⅰ)求数列 $\left\{a_n\right\}$的通项公式;
(Ⅱ)设数列 $\left\{b_n\right\}$满足 $\frac{b_1}{a_1}+\frac{b_2}{a_2}+\dots +\frac{b_n}{a_n}=1-\frac{1}{2^n}$ $\left(n\in N\right)$，求 $\left\{b_n\right\}$的前 $n$项和 $T_n$.