△ABC的三个顶点为A(2, 8), B(–4, 0), C(6, 0),则过点B将△ABC的面积平分的直线的方程为( )
A.2x–y+4=0 | B.x+2y+4=0 |
C.2x+y–4=0 | D.x–2y+4=0 |
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△ABC的三个顶点为A(2, 8), B(–4, 0), C(6, 0),则过点B将△ABC的面积平分的直线的方程为( )
A.2x–y+4=0 | B.x+2y+4=0 |
C.2x+y–4=0 | D.x–2y+4=0 |