已知抛物线y2 =8x的焦点为F,直线y=k(x+2)与抛物线交于A,B两点,则直线FA与直线FB的斜率之和为
复数=()
若复数z满足(3﹣4i)z=|4+3i|,则z的虚部为()
设复数z满足(1﹣i)z=2i,则z=()
i为虚数单位,若,则|z|=()
||=()