设抛物线 $C:y^2=4x$的焦点为 $F$,直线 $l$过 $F$且与 $C$交于 $A,B$两点.若 $\left|AF\right|=3\left|BF\right|$,则 $l$的方程为（）

A．	$y=x-1$或 $y=-x+1$
B．	$y=\frac{\sqrt{3}}{3}\left(x-1\right)$或 $y=-\frac{\sqrt{3}}{3}\left(x-1\right)$
C．	$y=\sqrt{3}\left(x-1\right)$或 $y=-\sqrt{3}\left(x-1\right)$
D．	$y=\frac{\sqrt{2}}{2}\left(x-1\right)$或 $y=-\frac{\sqrt{2}}{2}\left(x-1\right)$