已知椭圆$C:\frac{x^2}{2}+y^2=1$的两焦点为$F_1,F_2$,点$P(x_0,y_0)$满足$0<\frac{x^2}{2}+y_0^2<1$,则|$\left|P{F}_1\right|+\left|P{F}_2\right|$的取值范围为，直线$\frac{x_{0}x}{2}+y_{0}y=1$与椭圆$C$的公共点个数.