设集合$S=\left\{\overline{)x}\left|x\right|<5\right\},T=\left\{\overline{)x}{x}^2+4x-21<0\right\},$则$S\cap T$=

$\left\{\overline{)x}-7<x<-5\right\}$ $\left\{\overline{)x}3<x<5\right\}$ $\left\{\overline{)x}-5<x<3\right\}$ $\left\{\overline{)x}-7<x<5\right\}$