已知2Zn(s)＋O2(g)=2ZnO(s)ΔH＝－701.0 kJ·mol－1
2Hg(l)＋O2(g)
2HgO(s)ΔH＝－181.6 kJ·mol－1
则反应Zn(s)＋HgO(s)=ZnO(s)＋Hg(l)的ΔH为( )
| A．＋519.4 kJ·mol－1 | B．＋259.7 kJ·mol－1 |
| C．－259.7 kJ·mol－1 | D．－519.4 kJ·mol－1 |
相关试题
分析下表中各项的排布规律，按此规律排布第26项应为( )
| 1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
| C2H4 |
C2H6 |
C2H6O |
C2H4O2 |
C3H6 |
C3H8 |
C3H8O |
C3H6O2 |
C4H8 |
C4H10 |
A.C7H16 B．C7H14O2 C．C8H18 D．C8H18O
根据下表中烃的分子式排列规律，判断空格中烃的同分异构体数目是( )
| 1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
| CH4 |
C2H4 |
C3H8 |
C4H8 |
|
C6H12 |
C7H16 |
C8H16 |
A.3 B．4 C．5 D．6
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