一定条件下，可逆反应X（g）+3Y（g）
2Z（g）；若X、Y、Z起始浓度分别为C1、C2、C3（均不为0），平衡时X、Y、Z的浓度分别为0.1mol/L、0.3 mol/L、0.08 mol/L，则下列判断不合理的是 
| A．C1：C2=1:3 | B．平衡时，Y和Z的生成速率之比为3 ：2 |
| C．反应过程中X、Y的转化率不相等 | D．C1取值范围为0＜C1＜0.14 mol/L |
相关试题
My friend showed me round the town, ______ was very kind of him. 
| A．which | B．that | C．where | D．it |
They use computers to keep the traffic _______ smoothly.
| A．being run | B．run | C．to run | D．running |
If you leave the club, you will not be_____back in .
| A．received | B．admitted | C．turned | D．moved |
What I need is_____ book that contains ______ABC of oil painting.
| A．a; 不填 | B．the; 不填 | C．the; an | D．a ; the |
粤公网安备 44130202000953号