下面均是正丁烷与氧气反应的热化学方程式(25℃,101kPa):
①C4H10(g)+13/2O2(g)=4CO2(g)+5H2O(l);ΔH=-2878kJ/mol
②C4H10(g)+13/2O2(g)=4CO2(g)+5H2O(g);ΔH=-2658kJ/mol
③C4H10(g)+9/2O2(g)=4CO(g)+5H2O(l);ΔH=-1746kJ/mol
④C4H10(g)+9/2O2(g)=4CO(g)+5H2O(g);ΔH=-1526kJ/mol
由此判断,正丁烷的燃烧热是
A.-2878kJ/mol |
B.-2658kJ/mol |
C.-1746kJ/mol |
D.-1526kJ/mol |