某白色固体混合物由NaCl、KCl、MgSO 4、CaCO 3中的两种组成，进行如下实验：①混合物溶于水，得到澄清透明溶液；②做焰色反应，通过钴玻璃可观察到紫色；③向溶液中加碱，产生白色沉淀。根据实验现象可判断其组成为（ ）
A．KCl、NaCl B．KCl、MgSO 4
C．KCl、CaCO 3 D．MgSO 4、NaCl
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