将少量金属钠放入盛有CuSO4溶液的烧杯中,烧杯中发生的反应是
①2Na+CuSO4=Na2SO4+Cu
②Cu+2H2O=Cu(OH)2↓+H2↑
③2Na+2H2O=2NaOH+H2↑
④2NaOH+CuSO4=Cu(OH)2↓+Na2SO4
A.① | B.①② | C.③④ | D.①③ |
将少量金属钠放入盛有CuSO4溶液的烧杯中,烧杯中发生的反应是
①2Na+CuSO4=Na2SO4+Cu
②Cu+2H2O=Cu(OH)2↓+H2↑
③2Na+2H2O=2NaOH+H2↑
④2NaOH+CuSO4=Cu(OH)2↓+Na2SO4
A.① | B.①② | C.③④ | D.①③ |