室温下，将1$mol$的$CuS{O}_4$·$5H_{2}O\left(s\right)$溶于水会使溶液温度降低，热效应为$△H_1$，将1$mol$的$CuS{O}_4\left(s\right)$溶于水会使溶液温度升高，热效应为$△H_2$；$CuS{O}_4$·$5H_{2}O$受热分解的化学方程式为：$CuS{O}_4$·$5H_{2}0\left(s\right)$ △$CuS{O}_4\left(s\right)$+$5H_{2}O\left(l\right)$， 热效应为$△H_3$。则下列判断正确的是

$△H_2$＞ $△H_3$ $△H_1$＜ $△H_3$ $△H_1$+ $△H_3$ = $△H_2$ $△H_1$+ $△H_2$＞ $△H_3$