A、B、C、D、E五种元素原子序数依次增大,且均不超过18。其中A与C、B与E分别为同族元素。原子半径A<B<E<D<C,B原子最外层电子数是内层电子数的3倍,C、D原子的核外电子数之和与B、E原子的核外电子数之和相等。下列说法正确的是A.原子最外层电子数:B<AB.A与E形成的化合物是离子化合物C.B与E可以形成EB2型化合物D.最高价氧化物对应的水化物碱性:C<D
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