中学所学的A、B、C三种物质都是由H、O、S、Na中的三种元素组成的强电解质。A、B的水溶液均呈碱性，测得pH相等的A、B溶液c(A)<c(B)；C的水溶液呈酸性。有关说法正确的是
A．A是Na2SO3
B. B溶于溴水中，不可能生成沉淀
C. B、C反应的离子方程式可能是：SO3－＋2H＋→ SO2↑＋H2O
D. 若A、B两溶液的pH＝9，则两溶液中水电离的OH－的物质的量浓度之比为1:1
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