燃烧a g乙醇(液态),生成二氧化碳气体和液态水,放出的热量为Q KJ,经测定,a g乙醇与足量钠反应,能生成标准状况下的氢气5.6L,则乙醇燃烧的热化学方程式书写正确的是
A.C2H5OH(1)+3O2(g)=2CO2(g)+3H2O(1) △H =" -Q" KJ/mol |
B.C2H5OH(1)+3O2(g)=2CO2(g)+3H2O(1) △H =" -" Q / 2 KJ/mol |
C.1/2 C2H5OH(1)+3/2O2(g)=CO2(g)+3/2H2O(1) △H =" -Q" KJ/mol |
D.C2H5OH(1)+3O2(g)=2CO2(g)+3H2O(1) △H =" -2Q" KJ/mol |