2molCl2(g)与足量的H2(g)反应生成HCl(g),在298K时测得放出369.2kJ热量。则下列热化学方程式不正确的是
A.H2(g)+ Cl2(g)= 2HCl(g)△H =" -" 369.2kJ·mol-1 |
B.2H2(g)+2Cl2(g)= 4HCl(g)△H =" -" 369.2kJ·mol-1 |
C.HCl(g)= 1/2H2(g)+ 1/2Cl2(g)△H =" +" 92.3kJ·mol-1 |
D.1/2H2(g)+ 1/2Cl2(g)= HCl(g)△H =" -" 92.3kJ·mol-1 |