已知反应：①2K2CrO4+H2SO4=K2Cr2O7+K2SO4+H2O，
②K2Cr2O7+6FeSO4+7H2SO4=3Fe2(SO4)3+Cr2(SO4)3+K2SO4+7H2O，
③Fe2(SO4)3+2HI=2FeSO4+I2+H2SO4。下列结论正确的是（ ）
| A．①②③均是氧化还原反应 |
| B．氧化性强弱顺序是：K2Cr2O7＞Fe2(SO4)3＞I2 |
| C．反应②中氧化剂与还原剂的物质的量之比为6∶1 |
| D．反应③中0.1mol还原剂共失去电子数为1.2×1022 |
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