已知在1×105 Pa,298 K条件下,2g氢气燃烧生成水蒸气放出242 kJ热量,下列热化学方程式正确的是
A.2H2 ( g ) + O2 ( g ) = 2H2O ( l )△H = -484kJ/mol |
B.H2 ( g ) + 1/2O2 ( g ) = H2O ( g )△H = +242kJ/mol |
C.2H2+ O2 ="==" 2H2O△H = -484kJ/mol |
D.H2O ( g ) = H2 ( g ) + 1/2O2 ( g )△H = +242kJ/mol |