已知在1×105 Pa,298 K条件下,2 mol氢气燃烧生成水蒸气放出484 kJ热量,下列热化学方程式正确的是 ( )
A.H2O(g) ="=" H2(g)+1/2 O2(g);△H1=+242 kJ·mol-1 |
B.2 H2(g)+ O2(g)="==2" H2O(l);△H2=- 484 kJ·mol-1 |
C.H2(g)+1/2 O2(g)====H2O(g) ;△H1=+242 kJ·mol-1 |
D.2 H2(g)+ O2(g)="==2" H2O(g);△H2=+484 kJ·mol-1 |