在浓盐酸中H3AsO3与SnCl2反应的离子方程式为：3SnCl2＋12Cl－＋2H3AsO3＋6H＋=2As＋3SnCl62-＋6M，关于该反应的说法中正确的组合是
①氧化剂是H3AsO3 ②Sn Cl62-是氧化产物 ③每生成7．5 g As，还原剂失去的电子为0．3mol ④M为OH－
| A．①②③ | B．①②④ | C．①③④ | D．①②③④ |
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