在一个半径是20米的圆形苗圃边沿修一条2米宽的环行路．这条路面的面积是多少平方米？
直接写出计算结果．×12=÷= 1﹣10%=+= 4×25%= 18÷=
直接写出得数： 1﹣5%=+=×= 3÷= 6×=×=+=÷=÷12=﹣=
+=﹣= 298+76= 4.8÷0.01= 12×（×）= 0.25×12= 3.28×0×72%= 4.62+6.8= 3.75﹣2.8=÷=
===== 99×0.25+0.25== 7.2÷100﹣0.72÷10===
直接写出得数． 138+17= 83﹣57= 4708﹣999= 402×5= 20×500= 320÷80= 15.7+3= 10.9+1.09= 1﹣0.09= 0.9﹣0.26= 4×3.14= 3.25×4= 6.4÷0.8= 0.48÷0.03=+=+=×4=×= 24÷=+÷+=
×12=
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= 3÷
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×
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÷12=
﹣
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）= 0.25×12= 3.28×0×72%= 4.62+6.8=
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= 99×0.25+0.25=
= 7.2÷100﹣0.72÷10=
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×4=
×
= 24÷
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