△ABC中,D、E分别是边AB、AC上的点,BE、CD相交于点F,S△BDF=10,S△CEF=16,S△BCF=20,求△ABC面积.
÷50=0.12=.
= :24=5:8= :40= %
3÷ ==0.75=6: = %
3÷ ==0.6=6: = %.
3:5==9: == .