△ABC中，D、E分别是边AB、AC上的点，BE、CD相交于点F，S△BDF=10，S△CEF=16，S△BCF=20，求△ABC面积．
直接写得数．+= 1﹣= 1÷=﹣= 9.6÷1.6= 0÷= 51×199≈（+）×12=
直接写出得数 30╳=÷= 28╳= 1÷=+= 16÷=﹣=╳=
直接写出得数． 0÷= 0.3+= 82+28= 0.22×100=
直接写出得数．×4=×=÷=××= 1÷= 1÷=×0.75=×14+= 1﹣=+=÷5=÷×÷=
直接写得数+=﹣= 1÷= 7×=×3=+=﹣=÷=÷4= 3÷=+= 18×=
+
= 1﹣
= 1÷
=
﹣
=
= 51×199≈（
+
）×12=
=
÷
= 1÷
=
+
= 16÷
=
﹣
=
╳
=
=
=
×4=
×
=
÷
=
×
=
= 1
÷
=
×0.75=
×14+
﹣
=
+
=
÷
×
+
=
﹣
= 1÷
= 7×
=
×3=
+
=
﹣
=
÷
÷4= 3÷
=
+
= 18×
=
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