如图，A、B、C是三个顺次咬和的齿轮，当A转4圈时，B恰好转3圈：当B转4圈时，C恰好转5圈，则A、B、C的齿数的最小数分别是多少？
直接写得数． 3.14×25= 32÷40%= 789+198= 4521÷51≈（估算）÷= 3﹣﹣= 1÷0.01﹣10= ×9÷=
直接写出得数．11.7+3 0.5×90 12÷7×4.8 12÷ 12.5×8021÷7 3﹣1 +﹣+ 3×101﹣3．
直接写出得数．2.8+4.02= 2.5×41= 23.4÷10= 1.5+6﹣1.5﹣= 4.8÷12= ÷= 3.9×5×=
直接写出得数．23.6﹣8.8= += ×= 0÷= 0.24×5=36÷= 2.4÷40%= ×= 2.75﹣（+）= +×=
8.4÷0.7= ×33= ﹣= 0.25×4= 3﹣=÷25%= 4.8×= 3.37+6.63= +×2= ×=1﹣100%= 3.6×= 0.5﹣+0.5﹣= 12.6÷3= 1.02﹣0.43=1÷= 10﹣1.34﹣3.66= 8÷= 7+0÷7﹣7= ×13÷=
÷
= 3﹣
﹣
= 1÷0.01﹣10= 
×9÷
×4.8 12
÷
12.5×80
÷7 3
﹣1
+
×101﹣3
﹣
= 4.8÷12= 
= 3.9×5×
+
= 
×
= 0÷
= 2.4÷40%= 
×
= 2.75﹣（
+
）= 
+
×
×33= 
﹣
= 0.25×4= 3﹣
=
= 3.37+6.63= 
+
×2= 
×
=
= 0.5﹣
+0.5﹣
= 10﹣1.34﹣3.66= 8÷
= 7+0÷7﹣7= 
×13÷
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