有四个互不相等的自然数，最大数与最小数的差等于4，最小数与最大数的乘积是一个奇数，而这四个数的和是最小的两位奇数．求这四个数．
直接写出得数+= ﹣= 0÷6= 39×= 15﹣=1÷= 21÷= （+）×6= ×÷×= 8×﹣=
直接写出得数．= = = == = = =
口算．= = 5﹣= =0×1= 1÷= = =
直接写得数．= = = == = = =
直接写得数+= ÷7= ×= ÷=×8= 9÷= 15×= ﹣=÷= ×= ×= ÷=
+
= 
﹣
= 0÷6
= 39×
= 15﹣
=
= 21÷
= （
+
）×6= 
×
÷
×
﹣
=
= 
= 
= 
=
= 
= 
= 
=
= 
= 5﹣
= 
=
= 1÷
= 
= 
=
= 
= 
= 
=
= 
= 
= 
=
+
= 
÷7= 
×
= 
÷
=
×8= 9÷
= 15×
= 
﹣
=
÷
= 
×
= 
= 
÷
=
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