盒子里有2个红球，6个黄球。（1）任意摸出1个球，摸出哪种颜色的可能性大？（2）一次摸出2个球，可能出现哪几种结果？（3）至少摸出即个球，才能保证有1个黄球？
÷2=+= 10÷=×6=×=÷= 9×= 15×（﹣）=
直接写得数=== 15.7+3==== 10+10%= 3﹣3÷5= 0.9×99+0.9=
1﹣65%= 1﹣1÷6= 0.32= 40×5%=+= 25%÷= 1﹣+= 0.125×0.125=
看谁算得快×=×÷×= 0.35×99=÷= 79﹣0.79=+= 10÷1%= 32×1.25%=
直接写出得数．×== 1.25×0.16×8= 2.6﹣1.7= 44÷=×=××==×16+×16= 0.6+99×0.6=
÷2=
+
= 10÷
=
×6=
×
=
÷
= 9×
= 15×（
﹣
）=
=
=
= 15.7+3=
=
=
= 10+10%= 3﹣3÷5= 0.9×99+0.9=
+
= 25%÷
+
= 0.125×0.125=
×
=
×
÷
×
= 0.35×99=
÷
=
+
= 10÷1%= 32×1.25%=
×
=
=
=
×
=
×
×
=
=
×16+
×16= 0.6+99×0.6=
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