一个圆的周长为1.26米，两只蚂蚁从一条直径的两端同时出发沿圆周相向爬行，这两只蚂蚁每秒钟分别爬行5.5厘米和3.5厘米，在运动过程中它们不断地调头，如果把出发算作第零次调头，那么相邻两次调头的时间间隔依次是1秒，3秒，5秒，…，即是一个由连续奇数组成的数列．问：两只蚂蚁爬行了多长时间才能第一次相遇？
相关试题
×12=
÷
=
×
÷
÷1=
﹣
=
+
= 20÷
=
×21=
÷
= 2÷10%= 16×25%=
= 5.6÷0.08=
÷
= 36×10%=
=
×9×
=
﹣0÷
+1= 1÷
﹣
小时：120分= 7﹣7÷8=
﹣2.7= 14×
=
÷5=
1
=
=
=
=
﹣
=
=
=
=
=
= 24
=
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0.25×8= 3.4﹣
﹣
=
+0.5=
10.5﹣1.05=
= 10.01÷10%=
1.5×
=
80%= 1×9
=
3×
=
=（2）
=（3）
=（4）
=
=（6）
=（7）1.25×4×0.25=（8）
=
﹣
= 1÷
= 7×
= 3÷
=
÷4=
+
=
×
×8= 0÷
=
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