甲、乙各有糖若干块，每操作一次是由糖多的人给糖少的人一些糖，使得糖少的人的糖数增加一倍，经过三次这样的操作后，甲有5块糖，乙有12块糖，两个人原来的糖数分别是多少？
直接写出得数×=÷4= 7﹣= 1.2×=×=÷=÷2= 18÷=
直接写得数： 7.2×= 1÷==×0.3= 10÷0.1×10÷0.1= 3=+=== 18=
计算下面各题×=×8= 6×= 27﹣= 22÷=×= 54÷=+= 1﹣=﹣= 16×=÷=
直接写得数． 3×= 1÷=÷=+= 0÷=×=÷= 6×=
×4=×=+=×=×=÷= 0÷=×= 0×10=×=+=﹣= 0÷=÷=×4= 3×1=+=﹣= 1÷（﹣）= 4÷×4=
×
=
÷4= 7﹣
= 1.2×
=
×
=
÷
=
÷2= 18÷
=
= 1÷
=
=
×0.3=
=
+
=
=
= 18
=
×
=
×8= 6×
= 27﹣
= 22÷
=
×
=
=
+
= 1﹣
=
﹣
= 16×
=
÷
= 1÷
=
÷
=
+
=
=
×
=
= 6×
=
×4=
×
=
+
=
×
×
=
÷
= 0÷
×
= 0×10=
×
=
+
=
﹣
= 0÷
=
÷
=
×4=
1=
=
﹣
= 1÷（
﹣
）= 4÷
×4=
粤公网安备 44130202000953号