甲工程队每工作5天必须休息1天，乙工程队每工作6天必须休息2天．一项工程，甲工程队单独做需62天，乙工程队单独做需51天．请问：甲、乙两个工程队合作完成这项工程需要多少天？
直接写出得数======= 8×0.125=
直接写得数÷4=+=÷=×= 8×= 2÷= 1÷= 1﹣﹣= 2﹣= 2××=
直接写出得数．÷= 202﹣99= 3.5÷1000= 28÷1%= 34×50=×= 1.24÷0.4= 42×0.2=+=﹣=÷6= 1+99%=
直接写得数．== 1=== 2﹣===
直接写出得数． 2÷= 0.75÷0.25= 7×60%= 233﹣198= 175﹣75×=×= 4﹣= 5×23=×= 2×÷2×=
=
=
=
=
=
=
= 8×0.125=
÷4=
+
=
÷
=
×
= 8×
=
= 1÷
= 1﹣
﹣
= 2﹣
= 2×
×
=
÷
= 202﹣99= 3.5÷1000= 28÷1%=
×
= 1.24÷0.4= 42×0.2=
+
=
=
÷6= 1+99%=
=
= 1
=
=
= 2﹣
=
=
=
= 0.75÷0.25= 7×60%= 233﹣198= 175﹣75×
=
×
= 4﹣
= 5×23=
×
= 2×
÷2×
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