一个四位数ABCD，它与逆序数DCBA之和的末两位为56，这样的四位数ABCD有多少个？
×=÷6=÷= 1÷=×=﹣=+= 6÷= 0÷=×===
直接写出得数． 18×=÷= 0.25×3.2×4= 32×（1﹣0.99）= 25%×4= 0÷=÷=×÷×=
直接写得数 72×= 1.25×8= 2.9+6.1=+=÷=×= 25÷75=÷= 1.2×= 5÷=
直接写出得数． ①×4= ②0.5+1= ③3×= ④2﹣0.7= ⑤2÷0.7= ⑥3.5﹣﹣2= ⑦6×（+）= ⑧5.5×4+5.5×6= ⑨4﹣（+1）= ⑩4÷4=
直接写得数×15= =87﹣32= 0.62= 8﹣0.8= 3.2×4= 7.2÷4= 24÷= ×=﹣= ．
×
=
÷6=
÷
= 1÷
×
=
﹣
=
+
= 6÷
=
=
=
=
=
=
÷
= 0.25×3.2×4= 32×（1﹣0.99）=
÷
×
÷
= 1.25×8= 2.9+6.1=
+
=
÷
=
×
= 25÷75=
÷
=
= 5÷
=
×4= ②0.5+1= ③3
×
= ④2﹣0.7=﹣2
= ⑦6×（
+）= ⑧5.5×4+5.5×6=
﹣（+1
）= ⑩4
÷4=×4= ②0.5+1= ③3×= ④2﹣0.7=﹣2= ⑦6×（+）= ⑧5.5×4+5.5×6=﹣（+1）= ⑩4÷4=
×15= 
=87﹣32= 0.62= 
= 
×
=
﹣
= ．
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