有两个相邻的自然数，它们的各位数字之和均为7的倍数，这两个自然数中较小的数是多少？
直接写出得数． 2.8÷0.125= 4.38﹣3.42+5.62﹣2.08=== 9.08×9+9.08==
直接写出得数． ④36.36÷36= ②×= ③2.5×1.5×4=
直接写得数． 1÷0.05= 0.325+=（0.2）2= 10﹣0.01== 3.1×0.7=
1.45×5=×2.4=×3÷= 1.6×0.125= 4.7×9+4.7= 1.25×6.3×8= 6.5×2÷5= 15÷×=×2÷×2= 1÷﹣÷1=
直接写出得数 0.4+4.73======
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= 9.08×9+9.08=
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×
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=（0.2）2=
= 3.1×0.7=
×2.4=
×3÷
×
×2÷
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