一个直角三角形中，已知其中一个锐角是55，求另一个锐角是多少度？
直接写出得数．×16= 10÷= 12÷=×= ×= ÷3=×= ×=
6×= += ×= 3﹣= ÷=1÷= ÷= ﹣= ×14= ÷12=
直接写出得数．= = 71.83÷8≈ 5.04×9.85≈= = = 0.53=
直接写得数= = = = == = 60×60%= 2×32= =
直接写出得数．×8= ÷2= ×= ÷= ÷= ﹣0.6=×= ÷10= += ÷= 16×= 1﹣7%=
×16= 10÷
= 12÷
=
×
= 
×
= 
÷3=
×
= 
×
=
= 
+
= 
×
= 3﹣
= 
÷
=
= 
÷
= 
﹣
= 
×14= 
÷12=
= 
= 71.83÷8≈ 5.04×9.85≈
= 
= 
= 0.53=
= 
= 
= 
= 
=
= 
= 60×60%= 2×32= 
=
×8= 
÷2= 
×
= 
÷
= 
÷
×
= 
÷10= 
+
= 
= 16×
= 1﹣7%=
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