求角的度数．（1）AB=AC（如图1）∠1=∠2=（2）三角形ABC是等腰三角形（如图2）∠1=∠2= ．
直接写出复数．×= 1÷=÷8= 7×=×12=×=﹣=+=÷= 14÷=
直接写出得数． 0.56+0.25=﹣（﹣）= 0÷=（+）×6=+=×=8÷= 1+8%=
直接写结果﹣= 570÷×20=+3.5= 11﹣﹣=×= 1÷= 10﹣=÷= 19.9+19.9×99=
直接写出得数．﹣= 12×=÷26=+=×=+= 1÷=×=
口算﹣=+=×=÷7=
×
= 1÷
=
÷8= 7×
=
×12=
×
=
﹣
=
+
÷
= 14÷
=
﹣（
﹣
）= 0÷
=（
）×6=
+
=
×
=8÷
﹣
= 570÷
×20=
﹣
=
×
= 1÷
= 10﹣
=
÷
= 19.9+19.9×99=
﹣
= 12×
=
÷26=
+
=
×
=
+
= 1÷
=
×
=
﹣
=
+
=
×
=
÷7=
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