甲乙两车速度比7：5，如果甲乙分别从AB同时对开，小时相遇．如果他们分别从AB同向而行，甲几小时追上乙？
直接写出计算结果．×12=÷= 1﹣10%=+= 4×25%= 18÷=
直接写出得数： 1﹣5%=+=×= 3÷= 6×=×=+=÷=÷12=﹣=
+=﹣= 298+76= 4.8÷0.01= 12×（×）= 0.25×12= 3.28×0×72%= 4.62+6.8= 3.75﹣2.8=÷=
===== 99×0.25+0.25== 7.2÷100﹣0.72÷10===
直接写出得数． 138+17= 83﹣57= 4708﹣999= 402×5= 20×500= 320÷80= 15.7+3= 10.9+1.09= 1﹣0.09= 0.9﹣0.26= 4×3.14= 3.25×4= 6.4÷0.8= 0.48÷0.03=+=+=×4=×= 24÷=+÷+=
小时相遇．如果他们分别从AB同向而行，甲几小时追上乙？
×12=
÷
=
+
=
=
+
=
×
= 3÷
=
=
×
=
+
=
÷
=
÷12=
﹣
=
+
=
﹣
）= 0.25×12= 3.28×0×72%= 4.62+6.8=
=
=
=
=
= 99×0.25+0.25=
= 7.2÷100﹣0.72÷10=
=
=
+
=
+
=
×4=
×
= 24÷
=
+
粤公网安备 44130202000953号