甲、乙两地相距1053千米，一列客车和一列货车同时从两地相对开出，经过4.5小时相遇，已知货车的速度与客车的速度比是4：5，求客车和货车的速度各是多少？
直接写得数．10÷1%= 6.3×= 0×3.5= 4.2÷=1.125×8= ÷= 12﹣9.8= 3.6×2.5=1.25××8= ×2÷×2=
390×0.02= ﹣= 5﹣1.4﹣1.6= 0.9﹣0.26=81÷= 4×（0.6+1.9）= 0.23×400= ×=﹣+= 0.9+99×0.9=
口算．1.4×3= = = 1.8+0.32== 36.1÷5.9≈ 298×31≈ 499+203≈
直接写出下面各题的结果．28×2= 1.8+2.9= 4.8÷12= 10﹣0.9=0.25×4= ﹣= += ×=1﹣75%= ÷=
直接写得数3.3+6.07= 5×5%= 8÷1.6= 567﹣99=3÷27= 3﹣﹣= 5×÷5×= （+）×12=
= 0×3.5= 4.2÷
=
÷
= 12﹣9.8= 3.6×2.5=
×8= 
﹣
= 5﹣1.4﹣1.6= 0.9﹣0.26=
= 4×（0.6+1.9）= 0.23×400= 
×
=
﹣
+
= 0.9+99×0.9=
= 
= 1.8+0.32=
= 36.1÷5.9≈ 298×31≈ 499+203≈
﹣
= 
+
= 
×
=
÷
=
﹣
= 5×
÷5×
+
）×12=
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