甲、乙两地相距504千米，一辆汽车从甲地开往乙地，6小时行了全程的，以这样的速度，还需几小时到达乙地？（用比例解）
15÷0.25= 1.5×= 2.4+1= 1÷1.25×8= 24×== 10= 8+=×1.8=== 0.78+1+0.32=
直接写出得数． 1﹣45%= 0.4÷2.5= 15÷=×=÷=×=
口算． 8.1÷0.03=+3=×=﹣=×= 134﹣18= 1.5×4= 7.45+8.55= 25÷= 2.4﹣= 3.5×=×=
直接写得数． 3.14×22= 4÷6= 100×0.1%= 0.36+0.4= 3.75﹣1.25+0.25= 1.6×1.25= 734﹣198= 637÷8≈
直接写出得数． 304+198= 3﹣= 10×2= 1﹣4÷7= 7.5×= 5.2×6= 3.85×0+2.4= 21÷7=
，以这样的速度，还需几小时到达乙地？（用比例解）
= 2.4+1
= 1÷1.25×8=
=
= 10
= 8
+
=
×1.8=
=
= 0.78+1
+0.32=
=
×
=
÷
=
×
=
+3=
×
=
﹣
=
×
= 134﹣18= 1.5×4= 7.45+8.55=
= 2.4﹣
= 3.5×
=
×
=
= 10
×2= 1﹣4÷7=
= 5.2×6= 3.85×0+2.4= 21
÷7=
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