如图，甲、乙、丙三个互相咬合的齿轮，若使甲轮转5圈时，乙轮转7圈，丙轮转2圈，这三个齿轮齿数最少应分别是多少齿？
直接写出得数．×30= 2÷=÷=﹣=÷=××=+12.5%=÷=
直接写得数． 25×=÷6=×16=÷= 1÷=×=
直接写出得数÷= 20×=÷=﹣= 12÷50%= 3﹣﹣= 60×20%=÷26=+= 1﹣3%=
直接写出得数×4= 6﹣=÷= 6÷1%= 1÷=×=×0÷= 10+×=××5×7= 0.99×9+0.99=
直接得数．×21=×= 15÷=÷ 1﹣65%= 1+65%=÷=×=
×30= 2÷
÷
=
﹣
=
÷
=
×
×
=
+12.5%=
÷
=
=
÷6=
×16=
÷
= 1÷
=
×
=
÷
= 20×
÷
=
﹣
=
= 60×20%=
÷26=
+
= 1﹣3%=
×4= 6﹣
=
÷
= 6÷1%=
=
×
=
×0÷
×
=
×
×5×7= 0.99×9+0.99=
×21=
×
= 15÷
=
÷
÷
=
×
=
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