甲、乙 丙三个数，它们的平均数是95，其中甲数是90，乙数是97，求丙数是多少？
直接写出得数．47+16= 0.5×2.8= 0.14÷0.2=56×= ÷= ﹣=
a是自然数，2003÷大于2003． ．
直接写得数×4= 6﹣= ÷= 6÷1%=×0÷= 1÷= ×= 10+×=0.99×9+0.99= ×5×7=
直接写得数．10÷1%= 6.3×= 0×3.5= 4.2÷=1.125×8= ÷= 12﹣9.8= 3.6×2.5=1.25××8= ×2÷×2=
390×0.02= ﹣= 5﹣1.4﹣1.6= 0.9﹣0.26=81÷= 4×（0.6+1.9）= 0.23×400= ×=﹣+= 0.9+99×0.9=
= 
÷
= 
﹣
=
大于2003． ．
×4= 6﹣
= 
÷
= 6÷1%=
×0÷
= 1÷
= 
×
= 10+
×
=
×5×7=
= 0×3.5= 4.2÷
=
÷
= 12﹣9.8= 3.6×2.5=
×8= 
﹣
= 5﹣1.4﹣1.6= 0.9﹣0.26=
= 4×（0.6+1.9）= 0.23×400= 
×
=
﹣
+
= 0.9+99×0.9=
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