有A、B、C、D四个数，每次去掉一个数，将其余三个数求平均数，这样计算了四次，得到的结果分别是52、66、60、46，求A、B、C、D这四个数的平均数是多少？
直接写得数．×1=×=×12=×= 30×= 9×=×=×50= 6×=×=
算一算． 2×3 4×2 1×2×3× 11×3× 2××1．
直接写出得数．×8== 4.5+= 26×= 7﹣=×0×14= 6×= 5﹣=×6= 45×=
直接写出得数．×=×=×5=×=×= 42×π= 22×π= 32π=
口算．========
×1=
×
=
×12=
×
=
=
=
×
=
×50= 6×
=
×
=
×3
4
×2
1
×2
×3
×
11×3
×
2
×
．
×8=
= 4.5+
= 26×
= 7﹣
=
×0×14= 6×
= 5﹣
=
×6= 45×
=
×
×
=
×5=
×
=
×
= 42×π= 22×π= 32π=
=
=
=
=
=
=
=
=
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