如图由三角形ADG和三角形BCF拼成，直线AB将图形分成两部分，左边部分面积是38，右边部分面积是65．已知CD=5，DE=7，EF=15，FG=6．那么三角形ADG面积是多少？
直接写出得数．×8=÷2=÷=×=﹣= 6.8÷10%=×= 1÷=÷60%=×15= 4.5+=×=
直接写出得数×﹦ 9÷﹦÷﹦ 1×÷1×﹦﹢﹦×2﹦ 27×﹦ 0÷﹦÷1÷﹦××9﹦
直接写出得数．÷6= 15÷=×=÷= 42×=﹣60%= 10﹣99%= 40%×=
直接写出得数． 24×= 1÷=×12=×18÷3=÷=（﹣）×=×÷×=
直接写得数．============
×8=
÷2=
÷
=
×
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﹣
= 6.8÷10%=
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= 1÷
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÷60%=
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×
=
×
﹦ 9÷
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﹦ 1×
÷1×
﹦
﹢
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×2﹦ 27×
﹦ 0÷
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÷1
÷
×
×9﹦
÷6= 15÷
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= 42×
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﹣60%=
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= 1÷
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×12=
×18÷3=
÷
=（
﹣
）×
=
×
÷
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