把1到10，这10个自然数摆成一个圆圈，证明一定存在相邻的三个数，它们的和大于 17．
直接写出得数． 0.56+0.25=﹣（﹣）= 0÷=（+）×6=+=×=8÷= 1+8%=
直接写结果﹣= 570÷×20=+3.5= 11﹣﹣=×= 1÷= 10﹣=÷= 19.9+19.9×99=
直接写出得数．﹣= 12×=÷26=+=×=+= 1÷=×=
口算﹣=+=×=÷7=
直接写出得数． （1）1﹣0.25=（2）+= （3）2﹣=（4）0.5×= （5）20%÷=（6）×30%= （7）×=（8）0÷=
﹣（
﹣
）= 0÷
=（
）×6=
+
=
×
=8÷
﹣
= 570÷
×20=
﹣
=
×
= 1÷
= 10﹣
=
÷
= 19.9+19.9×99=
﹣
= 12×
=
÷26=
+
=
×
=
+
= 1÷
=
×
=
﹣
=
+
=
×
=
÷7=
+
=
=（4）0.5×
=
×30%=
×
=（8）0÷
=
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