一个运输队包运1998套玻璃茶具．运输合同规定：每套运费以1.6元计算，每损坏一套，不仅不得运费，还要从总费中扣除赔偿费18元．结果这个队实际得运费3059.6元．在运输过程中被损坏的茶具套数是多少？
直接写得数．×= += ﹣= +=×= ÷= ﹣= ×=14×= 20÷= 0×= ×23×1=
直接写出得数．﹣= 5﹣40%﹣1.6= ÷=3.14×102= ÷9= 2 5%×4=×= 6×÷6×=
直接写出得数．﹣= ÷= += ×= 1÷1%=
直接写出结果（近似值符号的只要求估算）．1﹣0.009= 0.25×101= 3÷0.03= 6π≈×= ÷= += 31×199≈
直接写得数320÷16= 10÷1%= 0.5×0.16= 3.3﹣1.95== = = =
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×
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×
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= 20÷
= 0×
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×23×1=
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= 5﹣40%﹣1.6= 
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÷9= 2 5%×4=
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= 6×
÷6×
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= 1÷1%=
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÷
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= 31×199≈
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